Sunday, August 22, 2021

S- Block Elements: Chemistry


  • Answers are in BOLD Option name.

 Q.1.  A Combustible gas is liberated when caustic soda solution is heated with 

A) S

B) NHblank subscript 4CI

C) Iblank subscript 2

D) Zn

Explanation-

2NaOH+Znrightwards arrow from blank to blank of Na subscript 2 ZnO subscript 2 plus space straight H subscript 2 upwards arrow
space space space space space space space space space space sodium space space space space space left parenthesis combusting
space space space space space space space space space space space zincate space space space space space space space space space space space space space gas right parenthesis 


Q.2.  On dissolving moderate amount of sodium metal in liquid ammonia at low temperature , which one of the following does not occur 

A) Blue coloured solution is obtained 

B) Nablank to the power of plus  ions are formed in the solution 

C) Liquid ammonia becomes good conductor of electricity 

D) Liquid ammonia remains diamagnetic 

Explanation-

Liquid ammonia solution becomes paramagnetic due to the presence of unpaired electron ions in the cavities in ammoniacal solution.


Q.3. Which of the following has largest size ?

A) Na

B) Nablank to the power of plus

C) Nablank to the power of minus

D) None of the above 

Explanation-

Anions has larger size than their parent atom.


Q.4.  When washing soda is heated 

A) CO is released 

B) CO+COblank subscript 2  is released 

C) COblank subscript 2  is released

D) Water vapour is released 

Explanation-

Na subscript 2 CO subscript 3.10 straight H subscript 2 straight O rightwards arrow from negative 9 straight H subscript 2 straight O to triangle of Na subscript 2 CO subscript 3. straight H subscript 2 straight O rightwards arrow from negative straight H subscript 2 straight O to triangle of Na subscript 2 CO subscript 3 


Q.5.  In Solvay ammonia process, sodium bicarbonate is precipitated due to 

A) Presence of NHblank subscript 3 

B) Reaction with COblank subscript 2 

C) Reaction with brine solution 

D) Reaction with NaOH

Explanation-

In Solvay ammonia process, sodium bicarbonate is precipitated due to common ion(Na to the power of plus) effect provided by brine (concentrated NaCl solution).


Q.6.  In electrolysis of NaCl , when Pt electrode is taken then Hblank subscript 2 is liberated at cathode while with Hg cathode it forms sodium amalgam . The reason for this is 

A) Hg is more inert than Pl

B) More voltage is required to reduce Hblank to the power of plus at Hg than at Pt 

C) Na is dissolved in Hg while it does  not dissolve in Pt

D) Concentration of  Hblank to the power of plus ions is larger when Pt electrode is taken 

Explanation-

More voltage is required to reduce straight H to the power of plus at Hg than at Pt.


Q.7.  When COblank subscript 2 is bubbled into an aqueous solution of Nablank subscript 2COblank subscript 3, the following is formed 

A) NaOH

B) NaHCOblank subscript 3

C) Hblank subscript 2O

D) OHblank to the power of minus 

Explanation-

Na subscript 2 CO subscript 3 plus CO subscript 2 plus straight H subscript 2 straight O rightwards arrow from blank to blank of 2 NaHCO subscript 3 


Q.8. Cs to the power of plus ion imparts violet color to the flame .This is due to the fact  that the emitted radiations have 

A) High energy 

B) Low energy 

C) Longer wavelength 

D) None of these 

Explanation-

Violet color corresponds to low wavelength or higher energy.


Q.9.  Sodium nitrate decomposes above 800degree C to give 

A) Nblank subscript 2

B) Oblank subscript 2

C) NOblank subscript 2

D) Nablank subscript 2O

Explanation-

2 NaNO subscript 3 rightwards arrow with greater than 800 degree straight C on top 2 NaNo subscript 2 plus straight O subscript 2 


Q.10. 1) The s- block elements of the periodic table are those in  which the last electron enters the s- subshell of the ________shell.

A) penultimate

B) antepenultimate

C) outermost          

D) foremost

Explanation-

Last electron , also called differentiating electron, enters the s- orbital of the last shell. Thus their general valence shell electron configuration is n s to the power of 1 minus 2 end exponent .










No comments:

Post a Comment

If you have any doubts, please let me know.