Wednesday, September 1, 2021

Chemical Equilibrium : Chemistry



 Q.1. What is incorrect about buffer solution ?

A) It contains a weak acid and its conjugate base.

B) It contains a weak base and its conjugate acid

C) It shows change in pH on adding small amount of acid or base

D) All of the above

Explanation-

Buffer resist any change in pH on adding small amount of acid or base,


Q.2. Which of the following species are Lewis acids ?

(I) O H to the power of minus

(II) F to the power of minus

(III) H to the power of plus

(IV) B C I subscript 3 

A) (I) and (II)

B) (III) and (IV)

C) (II) and (IV)

D) (I), (II) and (IV)

Explanation-

H to the power of plus and B C I subscript 3 are Lewis acids because they act as electron pair acceptors but O H to the power of minus and  F to the power of minus are Lewis bases because they act as electron pair donors.


Q.3.  P subscript open parentheses g close parentheses end subscript plus 3 Q subscript open parentheses g close parentheses end subscript left right double arrow 4 R subscript open parentheses g close parentheses end subscriptInitial concentration of P is equal to that of Q. The equilibrium concentration of P and R equal . Kblank subscript c is equal to 

A) 0.08

B) 0.8

C) 8

D) 1 over 8 

Explanation-

Let initial concentration of P and Q are equal and at equilibrium x concentration of P reacts , then 

space space space space space space space space space space space space space space space space space space space space space space space space space space space straight P subscript open parentheses straight g close parentheses end subscript space plus space 3 straight Q subscript open parentheses straight g close parentheses end subscript space leftwards harpoon over rightwards harpoon space 4 straight R subscript open parentheses straight g close parentheses end subscript
Initial space conc. space
open parentheses space moles space straight L to the power of negative 1 space end exponent close parentheses space space space straight C space space space space space space space space space space space space straight C space space space space space space space space space space space space space 0
At space equilibrium space open parentheses straight C minus straight x close parentheses space open parentheses straight C minus 3 straight x close parentheses space space space space space space space space 4 straight x
But space it space is space given space that space open parentheses straight C minus straight x close parentheses space space equals space space 4 straight x
therefore space straight C equals 5 straight x
straight K subscript straight c equals fraction numerator open square brackets straight R close square brackets to the power of 4 over denominator open square brackets straight P close square brackets open square brackets straight Q close square brackets cubed end fraction equals fraction numerator open parentheses 4 straight x close parentheses to the power of 4 over denominator open parentheses 4 straight x close parentheses open parentheses 5 straight x minus 3 straight x close parentheses cubed end fraction equals fraction numerator 64 straight x cubed over denominator 8 straight x cubed end fraction equals 8 


Q,4,  A chemical reaction A space left right double arrow space B is said to be in equilibrium when 

A) Complete conversion of A to B has taken place

B) Conversion of A to B is only 50% complete 

C) Only 10% conversion of A to B has taken place

D) The rate of transformation of A to B is just equal to rate of transformation of B to A in the system

Explanation-

At equilibrium , rate of forward reaction is equal to rate of back forward reaction is equal to rate of backward reaction .


Q.5.  Two mole of PCIblank subscript 5 are heated in a hosed vessel of 2 litre capacity . When the equilibrium is attained, 40%  of it has been found to be dissociated . What is Kblank subscript c in mol/dmblank cubed ?

A) 0.532

B) 0.266

C) 0.133

D) 0.174

Explanation-

space space space space space space space space space space space space space space space space space PCI subscript 5 space space rightwards harpoon over leftwards harpoon space space PCI subscript 3 space space plus space space CI subscript 2
stack Initial space conc with left parenthesis mol space straight L to the power of negative 1 end exponent right parenthesis below space. space 2 over 2 equals 1 space space space space space space 0 space space space space space space space space space space space 0
At space equilibrium space 1 minus 0.4 space space space 0.4 space space space 0.4
equals 0.6
straight K subscript straight c equals fraction numerator open square brackets PCI subscript 3 close square brackets open square brackets CI subscript 2 close square brackets over denominator open square brackets PCI subscript 5 close square brackets end fraction equals fraction numerator 0.4 cross times 0.4 over denominator 0.6 end fraction equals 0.266 


Q.6.  4 moles of A are mixed with 4 moles of B , when 2 moles of C and D are formed at equilibrium according to the reaction , A+B left right double arrow  C+D the value of equilibrium constant is 

A) 4

B) 1

C) 1/2

D) 1/4

Explanation-

space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space straight A space plus space straight B space rightwards harpoon over leftwards harpoon space straight C space plus space straight D
Initial space moles space space space space space space space space space space space space space 4 space space space space space space 4 space space space space space space space space 0 space space space space space space 0
At space equilibrium space space space space space open parentheses 4 minus 2 close parentheses space left parenthesis 4 minus 2 right parenthesis space 2 space space space space space space 2
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 2 space space space space space equals 2
space space space space space space space space space space straight K equals fraction numerator open square brackets straight C close square brackets open square brackets straight D close square brackets over denominator open square brackets straight A close square brackets open square brackets straight B close square brackets end fraction equals fraction numerator 2 cross times 2 over denominator 2 cross times 2 end fraction equals 1 


Q.7.  In which of the following cases, the reaction goes farthest to completion 

A) K = 10blank cubed 

B) K = 10blank squared 

C) K = 10

D) K = 10blank to the power of 0 

Explanation-

Greater the value of K, reaction is favored in forward direction.


Q.8.  The equilibrium constant , K for the reaction , 2 H I subscript open parentheses g close parentheses end subscript rightwards harpoon over leftwards harpoon H subscript 2 open parentheses g close parentheses end subscript plus I subscript 2 open parentheses g close parentheses end subscript  at room temperature is 2.85 and that at 698 K is 1.4 cross times 10 to the power of negative 2 end exponent . This implies that 

A) HI is an acidic compound

B) HI is very stable at room temperature 

C) HI is relatively less stable than Hblank subscript 2 and Iblank subscript 2

D) HI is resonance stabilized 

Explanation-

Equilibrium constant K is decreasing with increasing temperature. It shows that reaction is exothermic in forward direction which ultimately means that energy of HI is more than that of H subscript 2 space o r space I subscript 2. Hence, HI relatively less stable than H subscript 2 space o r space I subscript 2.


Q.9.  The gaseous reaction A+B rightwards harpoon over leftwards harpoon 2 C + D +q is most favored at

A) High temperature and low pressure 

B) Low temperature and low pressure 

C) Low temperature and High pressure 

D) High temperature and high pressure 

Explanation-

A plus B rightwards harpoon over leftwards harpoon 2 C plus D plus q The given reaction is endothermic and accompanied with increase in number of moles. Thus, favored at low temperature and low pressure.


Q.10. In a lime kiln , to get higher yield of COblank subscript 2 , the measure that can be taken is 

A) To maintains high temperature 

B) To pump out COblank subscript 2

C) To remove CaO

D) To add more CaCOblank subscript 3 

Explanation-

C a C O subscript 3 left parenthesis s right parenthesis end subscript rightwards harpoon over leftwards harpoon C a O subscript left parenthesis s right parenthesis end subscript plus C O subscript 2 left parenthesis g right parenthesis end subscript Removal of C O subscript 2 from the reaction mixture shift the reaction in a direction in which more of C O subscript 2 is formed 



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